find_largest_pow10()

int nlohmann::detail::dtoa_impl::find_largest_pow10 ( const std::uint32_t  n, std::uint32_t &  pow10  )

inline

For n != 0, returns k, such that pow10 := 10^(k-1) <= n < 10^k. For n == 0, returns 1 and sets pow10 := 1.

Definition at line 15994 of file json.hpp.

{
    // LCOV_EXCL_START
    if (n >= 1000000000)
    {
        pow10 = 1000000000;
        return 10;
    }
 
    // LCOV_EXCL_STOP
    if (n >= 100000000)
    {
        pow10 = 100000000;
        return  9;
    }
 
    if (n >= 10000000)
    {
        pow10 = 10000000;
        return  8;
    }
 
    if (n >= 1000000)
    {
        pow10 = 1000000;
        return  7;
    }
 
    if (n >= 100000)
    {
        pow10 = 100000;
        return  6;
    }
 
    if (n >= 10000)
    {
        pow10 = 10000;
        return  5;
    }
 
    if (n >= 1000)
    {
        pow10 = 1000;
        return  4;
    }
 
    if (n >= 100)
    {
        pow10 = 100;
        return  3;
    }
 
    if (n >= 10)
    {
        pow10 = 10;
        return  2;
    }
 
    pow10 = 1;
    return 1;
}